Question

the nucleus of an iron atom has a radius of 4×10=15m and contains 26protons what repulsive electrostatic force act between two protons in such a nucleus?​

Answer 1

Answer:

plz brainliest

Explanation:

Charge of proton is q

p

=1.6×10

−19

C

Distance between the ptoton is r=3×10

−15

m

The magnitude of electrostatic force between protons is

F

e

=

4πε

0

r

2

q

p

q

p

=

(3×10

−15

)

2

9×10

9

×1.6×10

−19

×1.6×10

−19

=25.6N