the number 2272 and 875 are divided by three digit number N,giving the same reminder. the sum of the digits of N is -----
Answers
Answered by
11
= 2272 - 875
= 1397
now , 1397= 11× 127
the required 3 digits number is 127 .
1+2+7= 10
= 1397
now , 1397= 11× 127
the required 3 digits number is 127 .
1+2+7= 10
keddaar:
sisy plz explain it more
i cant explain it more ..
u have given the same answer as it has written in rs agarwal book
I think you just copy paste
Answered by
5
2272=x×N +R..................eqn(i.)
875=y×N+R......................eqn(ii.)
subtracting (ii) from (i) we get,
1397=(x-y)×N
N=127
sum of digits of N= 7+2+1=10
875=y×N+R......................eqn(ii.)
subtracting (ii) from (i) we get,
1397=(x-y)×N
N=127
sum of digits of N= 7+2+1=10
Similar questions