Math, asked by bhoodevsharma9, 5 hours ago

The number 4 n where n is a natural number ends with the digits 0 for any natural number

Answers

Answered by vijayadate19

0

Step-by-step explanation:

Prime factor of 4n= (2x2)n

= 2n x 2n

therefore 5 is not a factor of 4n

4n cannot be divisible by 5.

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