Question

the number 4121 ,4973 and 6464 leave the same number x in each case when divided by the greatest number y. the value of(2y-x) is

Answer 1

Solution :-

The greatest number that divides 4121 ,4973 and 6464 leave the same number in each will be HCF of (4973 - 4121) , (6464 - 4973) and (6464 - 4121) .

so ,

→ 4973 - 4121 = 852

→ 6464 - 4973 = 1491

→ 6464 - 4121 = 2343

then, prime factors of 852, 1491 and 2343 are :-

→ 852 = 2 * 2 * 3 * 71

→ 1491 = 3 * 7 * 71

→ 2343 = 3 * 11 * 71

so,

→ HCF = 3 * 71 = 213 = y

then,

→ x = 4121 ÷ 213 = 74

therefore,

→ (2y - x)

→ 2 * 213 - 74

→ 426 - 74

→ 352 (Ans.)

Learn more :-

वह छोटी से छोटी संख्या बताईये जिसमे 7,9,11 से भाग देने पर 1,2,3 शेष बचे

https://brainly.in/question/9090122