The number 525 and 3000 are divisible by 3,5,15,25 and75 what is the HCF pls do it fast guy ' s
Answers
Answered by
14
Hii friend,
Prime factorisation of 525 = 5× 5 × 3 × 7
Prime factorisation of 3000 = 2 × 2 × 2 × 3 × 5 × 5 × 5
Therefore,
HCF of 525 and 3000 = 5 × 5 × 3 = 75
HOPE IT WILL HELP YOU...... :-)
Prime factorisation of 525 = 5× 5 × 3 × 7
Prime factorisation of 3000 = 2 × 2 × 2 × 3 × 5 × 5 × 5
Therefore,
HCF of 525 and 3000 = 5 × 5 × 3 = 75
HOPE IT WILL HELP YOU...... :-)
Answered by
2
hye
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there are 2 methods of solving it
1st method: the 2 numbers are 525 and 3000
they are divisible by 3,5,15,25 and 75 .
what is hcf?
hcf is the highest common factor.
so here the hcf in [3,5,15,25 and 75 ]
is 75 as it highest
so hcf of 525 and 3000 is 75
2nd method: lets recall a property
=>hcf *lcm = product of 2 numbers
=> lcm of 525 and 3000 = 21000[solve it by prime fctoisation]
=>hcf * 21000 = 525 *3000
=> hcf * 21000 = 1575000
=>hcf = 1575000/21000
=> hcf = 75
===================
hope it helps u ........
==============================
there are 2 methods of solving it
1st method: the 2 numbers are 525 and 3000
they are divisible by 3,5,15,25 and 75 .
what is hcf?
hcf is the highest common factor.
so here the hcf in [3,5,15,25 and 75 ]
is 75 as it highest
so hcf of 525 and 3000 is 75
2nd method: lets recall a property
=>hcf *lcm = product of 2 numbers
=> lcm of 525 and 3000 = 21000[solve it by prime fctoisation]
=>hcf * 21000 = 525 *3000
=> hcf * 21000 = 1575000
=>hcf = 1575000/21000
=> hcf = 75
===================
hope it helps u ........
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