The number 6n2+6n for natural number n is always divisible by
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The given number is
= 6 n² + 6 n
= 6 n (n + 1), where n is any Natural number
So, we see that the given number is always divisible by 6n, where n belongs to the set of Natural numbers and in particularly, it can be said that the number is always divisible by 6, and thus by 2 and 3.
#MarkAsBrainliest
The given number is
= 6 n² + 6 n
= 6 n (n + 1), where n is any Natural number
So, we see that the given number is always divisible by 6n, where n belongs to the set of Natural numbers and in particularly, it can be said that the number is always divisible by 6, and thus by 2 and 3.
#MarkAsBrainliest
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