Question

The number 832n is a multiple of 6,where n is a digit. Find all the possible values of n.

Answer 1

For a number to be divisible by 6, it should be divisible by 2 and 3.
So,
According to divisibility rule of 2 , n = 2,4,6,8,0.
And, According to divisibility rule of 3, we will check these values ...
8+3+2+2= 15, Divisible by 3 .
8+3+2+4= 17
8+3+2+6=19
8+3+2+8= 21, Divisible by 3.
8+3+2+0= 13.

Thus, the possible values for n = 2 and 8.

Hope it will help....

Answer 2

for multiple of 6.. no has to multiple of 2 nd 3 both..

for 2 : n should be even 2 4 6 8 0

nd for multiple of 3.

8 +3 +2+n =sum

should be multiple of 3..

from here we get

only possible value of n are. 2,8