the number consists of two digits in which the tens digit exceeds the unit unit digit by 6 the number itself is equal to 10 times the sum of digits find the number
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Let the two digit no be 10x +y where x is the tens digit and y is the once digit
A. To. Q
x=y+6
x-y=6----------------(1)
10x+y =10(x+y)
10x+y =10x+10y
y=0
So x=6
So no is 60
A. To. Q
x=y+6
x-y=6----------------(1)
10x+y =10(x+y)
10x+y =10x+10y
y=0
So x=6
So no is 60
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