Question

the number consists of two digits, the difference of whose digit is 3. if four times the number is equal to 7 times the number obtained by reversing the digits find the number.​

Answer 1

Answer: Suppose the tens digit is a and ones is b

then the two digit number is 10a+b

according to question ,a~b=3(a difference b)..............eq.1

and 4(10a+b)=7(10b+a)

⇒40a+4b=70b+7a

⇒33a=66b

⇒a=2b ...............eq.2

from eq1

if a>b then 2b-b=3

⇒b=3

if b>a then b-2b=3

⇒-b=3

⇒b=-3 { which is not applicable}

so a =2*3=6 [eq 2]

therefore the number =10*6+3=63

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