the number is divisible by both 7 and 9 by which another two numbers will that number will divisible
Answers
Answer:
63 was your answer
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Answer:
1 and 63
or
3 and 21
or
7 and 9
Step-by-step explanation:
Let the number be x and in its lowest form,
I said lowest because 2x is also divisible by 7 and 9
Similarly,
3x,4x,5x......and so on are all divisible by 7 and 9
so, x is the lowest number which is divisible by both 7 and 9
Now, if both 7 and 9 must be divisible then it must be its Lowest Common Multiple or for short LCM
so, LCM of 7 and 9 is 63
You may ask why I have taken LCM because this number that we are choosing should have both factors 7 and 9, also, it must be the lowest one
so, we took LCM, Hoping you understood it
Thus, Next we must find the factors of 63
63 = 1, 3, 7, 9, 21, 63
Now,
63 = 1 × 63
63 = 3 × 21
63 = 7 × 9
Now we can choose any two numbers
1 and 63
or
3 and 21
or
7 and 9
Hope it helped and you understood it........All the best