Question

The number obtained by reversing a two digit number is 18 more than the original number. If the sum of its digits is 8. find the number

Answer 1

Anwser

35

Step-by-step explanation:

let number be xy(10x+y) when reversers is 18 more

10x+y+18=10y+x

9(y-x)=18

y-x=2 eq 1;x+y=8 eq2

eq (1+2) x=3,y=5

number is 35

Answer 2

Answer:

35

Step-by-step explanation:

Let the digit in the unit place be x

Let the digit in tens place be y

Hence the number is x+10y

Given

x+y=8 or y=8-x

Also given

$x + 10y + 18 = 10x + y$

$x + 10(8 - x) + 18 = 10x + 8 - x$

$x + 80x - 10x + 18 = 10x + 8 - x$

$18x = 90$

$x = 5$

hence

$y = 3$

Hence the number is 35