The number obtained by reverting the digits is 594 less than the original number.The number is
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Answered by
7
hey
let the original number be X
then,
reversing digit= 594
hence real no. will 495
now,
495-x=594
x=594-495
x=101
let the original number be X
then,
reversing digit= 594
hence real no. will 495
now,
495-x=594
x=594-495
x=101
Answered by
2
Hey,
Let the original number be 10(x+y),
10(y+x) = 594 - 10(x+y)
10y + 10x = 594 - 10x - 10y
20x + 20y = 594
x+y = 594 / 20
x+y = 29.7
So, x = 29.7 - y
Now substitute X's value in the original number,
10(29.7 - y + y)
297.
So, required number is 297.
HOPE THIS HELPS YOU BUDDY!!
Let the original number be 10(x+y),
10(y+x) = 594 - 10(x+y)
10y + 10x = 594 - 10x - 10y
20x + 20y = 594
x+y = 594 / 20
x+y = 29.7
So, x = 29.7 - y
Now substitute X's value in the original number,
10(29.7 - y + y)
297.
So, required number is 297.
HOPE THIS HELPS YOU BUDDY!!
myselfyiri:
oh!! I thought the same :-|
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