Math, asked by tanhatanveer1537, 1 year ago

The number of 1's present in the binary re of 10 × 256 + 5 × 16 + 5 is

Answers

Answered by Gnanaprakasham
1
2560+80+5=2645

I hope it is the answer

❇❇✌✌by Sri ✌✌❇❇
Answered by PavethaSri
2

10 \times 256 + 5 \times 16 + 5 \\  = 2560 + 80 + 5 \\  = 2625

I hope it is the answer

NithishStephenNirmal: hi
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