the number of 3 digit number formed by using digits 3,5,9 taking each digit exactly once is
TARUN2693:
3*2*1 = 6
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359,953,395,935,539,593
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0
Answer:
All possible numbers are 359,395,539,593,935 and 953
Step-by-step explanation:
Given: digits 3,5,9 taking each digit exactly once
To find: Number of 3 digit number formed by using digits 3,5,9 taking each digit exactly once
Solution:
Using the digits 3,5,9, and taking each digit exactly once, possible 3- digit numbers are -
1. Taking 3 at hundreds place - 359,395
2. Taking 5 at hundreds place - 539,593
3. Taking 9 at hundreds place - 935,953
So, all possible numbers are 359,395,539,593,935 and 953
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