Math, asked by saloni138, 1 year ago

the number of 3 digit number formed by using digits 3,5,9 taking each digit exactly once is


TARUN2693: 3*2*1 = 6

Answers

Answered by saniya2326
24
359,953,395,935,539,593

TARUN2693: 3*2*1 = 6
Answered by ravilaccs
0

Answer:

All possible numbers are 359,395,539,593,935 and 953

Step-by-step explanation:

Given: digits 3,5,9 taking each digit exactly once

To find:  Number of 3 digit number formed by using digits 3,5,9 taking each digit exactly once

Solution:

Using the digits 3,5,9, and taking each digit exactly once, possible 3- digit numbers are -

1. Taking 3 at hundreds place - 359,395

2. Taking 5 at hundreds place - 539,593

3. Taking 9 at hundreds place - 935,953

So, all possible numbers are 359,395,539,593,935 and 953

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