Question

The number of 3-digit numbers divisible by 6, is ………….. .

Answer 1

Thus, the least 3-digit number divisible by 6 is 102. So, the largest 3 digit number divisible by 6 is 996. We know that the 3-digit numbers divisible by 6, form an Arithmetic Progression.

Answer 2

Answer:

149

Step-by-step explanation:

The least 3-digit number that is divisible by 6 is 102 and the greatest 3-digit number that is divisible by 6 is 996.

Use geometric equation:

nth term=$ar^(n-1)$

a= first term=102

r=common ratio=6

nth term=last term (in this case)=996

996=102×6^(n-1)

996=102×(6^n/6)

996=17×6^n

996/17=6^n

6^166/6^17=6^n

6^(166-17)=6^n

6^149=6^n

∴n=149