Math, asked by viswanand7536, 1 year ago

The number of 593is a term of an Ap formed by the terms 5,9,13,is it true check it and find the number of this term

Answers

Answered by dhanyapunnakkal
0

Answer:


Step-by-step explanation:

AP:5,9,13   a=5    d=4             593= 5+(n-1)4     593-5=4n-4     592/4 =n     n=148                                                                

Answered by Anonymous
5

Given :

  • First term = 5
  • Common difference = 9 - 5 = 4
  • Last term = 584

To find :

  • Number of terms in A.P

Solution :

By using A.P formula

 \tt \large A_n = a + (n - 1)d \\  \\   \tt \implies593 = 5 + (n - 1)4 \\  \\ \tt \implies593 - 5 = (n - 1)4 \\  \\ \tt \implies588 = (n - 1)4 \\  \\ \tt \implies \frac{588}{4}  = n - 1 \\  \\ \tt \implies147 = n - 1 \\  \\ \tt \implies  n = 147 + 1 \\  \\  \large \boxed{ \tt  \green{n = 148}}

Given number is 148th term of the A.P

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