Question

the number of atoms in 20 g of CaCO 3 is approximately

Answer 1

Answer:

Molecular weight of CaCO3 is 100

So, number of moles present in 20g of CaCO3

are 20/100=0.2

Each molecule of CaCO3

has 5 atoms. So, total no. of atoms present are 0.2×5.Na=6.023×10 ²³