Question

The number of atoms of carbon present in the mass equal to 24.092 x 10 molecules of methane.
1) 5.33 x 10 atoms
2) 32.0866 x 10-3
127
3) 18.061 <10 atoms
47 24.092 x 10°​

Answer 1

#HINT

no of atoms in a molecule=Mole(n)*atomicity*Na-----(1)

no of molecules=n*Na

n=no of molecules/Na-----subs in (1)

now find the no of carbon atoms....

atomicity=1

because one c in CH4

Na=avagadro numb

no of molecules given

sorry if explanation is wrong