The number of atoms of oxygen present in the same number of moles of baking soda as are present in 100 g of glucose (C6H12O6) is approximately
(a) 9.9126 × 10^20
(b) 19.1261 × 10^23
(c) 8.1121 × 10^23
(d) 9.9363 × 10^23
Answers
Answered by
1
Answer:
c.
Explanation:
i know only the answer but not reason
Answered by
0
Answer:
answer is c only
Explanation:
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