the number of atoms of sodium in 53g of na2co3 is
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Answered by
10
In (23×2+12+48)g Na2CO3 we have 46g of Na
now, in 53g of Na we will have 46×53/106 g of Na
=>in 53g of Na we will have 23 g of Na
1 mole Na = 23g Na = 6.023×10^23 atoms of Na
now, in 53g of Na we will have 46×53/106 g of Na
=>in 53g of Na we will have 23 g of Na
1 mole Na = 23g Na = 6.023×10^23 atoms of Na
Answered by
6
we know in 1 mol of Na2Co3,2 mol of Na is present.
Therefore,
in 53g of Na2Co3 where its molar mass is 106 its mol is 53÷106=0.5
therefore, in 0.5 mol of Na2Co3 Na contain :- 0.5×2=1 mol of Na
Hope it will help!!
Any doubt regarding this u can ask!!
pritomsaha26pdtw6y:
so the no. of atom will be =mol×NA=1×6.022×10^23
yep
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