Question

The number of atoms present in 16 g of oxygen is
(1) 6.02 x 1011.5 (2) 3.01 x 1023
(3) 3.01 1011.5 (4) 6.02 x 1023​

Answer 1

Explanation:

ans. b

3.011×10 23.......

Answer 2

Given ,

Mass of O2 = 16 gram

Molecular mass of O2 = 32 u

We know that ,

$\large \sf \pink{ \fbox{Number \: of \: particles = \frac{given \: mass \: }{molecular \: mass} \times 6.022 \times {10}^{23} } }$

Substitute the values , we obtain

$\sf = \frac{16}{32} \times 6.022 \times {10}^{23} \\ \\ \sf = 0.5 \times 6.022 \times {10}^{23} \\ \\ \sf = 3.011 \times {10}^{23} \: \: mol$

Therefore , the number of particles is 3.011 × 10²³