Question

The number of bacteria is continuously growing and it is doubled every 9 hours. If
there was 720 bacteria at 6 AM, what is the number of bacteria at 4 PM?​

Answer 1

Answer:

It is given that the number of bacteria doubles every hour.

Therefore, the number of bacteria after every hour will form a G.P.

with first term (a=30) and common ratio (r=2)

∴a

3

​

=ar

2

=(30)(2)

2

=120

Therefore, the number of bacteria at the end of 2nd hour will be 480.

a

5

​

=ar

4

=(30)(2)

4

=480

and a

n+1

​

=ar

n

=(30)(2)

n

Thus the number of bacteria at the end of nth hour will be (30)(2)

n

Step-by-step explanation:

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