The number of boys and girls in a class are in the ratio 7 is to 5 the number of boys is 8 more than the number of girls what is the total class strengthth
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Answered by
28
Given the ratio between the number of boys and girls in a class is 7 : 5
let the number of boys and girls be 7x and 5x respectively.
ATQ, the number of boys in the class is 8 more than the number of girls.
➡ no. if girls + 8 = no. of boys
➡ 5x + 8 = 7x
➡ 5x - 7x = -8
➡ -2x = -8
➡ x = -8/-2 = 4
therefore,
- no of girls = 5x = 5 × 4 = 20
- no. of boys = 7x = 7 × 4 = 28
hence, the total strength of the class = no. of girls + no. of boys
= 20 + 28
= 48 students
Answered by
19
Answer:
Let the number of girls = x
Number of boys = x + 8
According to the problem given,
Ratio of boys and girls = 7 : 5
( x + 8 ) : x = 7 : 5
Product of the means = product of
the extremes
x * 7 = ( x + 8 ) * 5
7x = 5x + 40
7x - 5x = 40
2x = 40
x = 40 /2
x = 20
Therefore ,
Number of girls = x = 20
Number of boys = x + 8 = 20 + 8 = 28
Total students = number of girls +
number of boys
= 20 + 28 = 48
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