Question

The number of boys and girls in a class are in the ratio 7 : 5.The number of boys is 8 more than the number of girls. What is the total class strength? ​

Answer 1

Answer:

48

Step-by-step explanation:

let the no of boys =x

let the no of boys =xlet the no of girls =y

let the no of boys =xlet the no of girls =yATQ

let the no of boys =xlet the no of girls =yATQ CASE 1

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20PUTTING THE VALUE OF (y) IN EQUATION (ii)

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20PUTTING THE VALUE OF (y) IN EQUATION (ii) =>x=20+8

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20PUTTING THE VALUE OF (y) IN EQUATION (ii) =>x=20+8=>x=28

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20PUTTING THE VALUE OF (y) IN EQUATION (ii) =>x=20+8=>x=28Ans =TOTAL STRENGTH OF CLASS =x+y

let the no of boys =xlet the no of girls =yATQ CASE 1=>x/y=7/5=>x=7y/5 - equation(i)CASE 2the no of boys is 8 more than the girls =>x=y+8 - equation(ii)PUTTING THE VALUE OF (x) IN EQUATION (ii)=>7y/5=y+8=>7y=5y+40=>7y-5y=40=>2y=40=>y=40/2=>y=20PUTTING THE VALUE OF (y) IN EQUATION (ii) =>x=20+8=>x=28Ans =TOTAL STRENGTH OF CLASS =x+y =28+20

=48

Answer 2

Step-by-step explanation:

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GIVEN :-

Ratio of number of boys to number of girls is 7:5

Number of boys is 8 more than Number of girls

TO FIND :-

Total strength of the class

SOLUTION :-

Let

Number of boys be 7x

Number of girls be 5x

We are given,

Number of boys is 8 more than Number of girls

$\implies \sf \: 7x = 5x + 8 \\ \\ \implies \sf \: 7x - 5x = 8 \\ \\ \implies \sf \: 2x = 8 \\ \\ \implies \sf \: x = \frac{8}{2} \\ \\ \implies {\underline {\bold {\boxed {\pink {\sf{x = 4}}}}}} \\ \\ \\ \\ </p><p>Then ,$

Then;

$] \sf \: Number \: of \: boys \: = 7x = 7(4) = 28 \\ \\ \sf Number \: of \: girls = 5x = 5(4) = 20$

Total class strength = Number of girls + Number of boys

$\implies \sf \: Total \: class \: strength = 20 + 28 \\ \\ \implies {\underline {\bold {\boxed {\blue {\sf{Total \: class\: strength \: = 48}}}}}}$

∴ Total Strength of the class is 48

$]\huge\orange{\mid{\fbox{\tt{Thanks}}\mid}}$