Math, asked by MdAjajul388, 1 year ago

the number of boys and girls in a class are in the ratio 7:5 the number of boys is 8 more than the number of boys and girls. what is the total class strength?​

Answers

Answered by ptgangadharmay3
75

Answer:

Step-by-step explanation:

let no. of boys be 7x

 no. of girls be 5x

A/q

      7x = 8 + 5x

   or, 7x - 5x = 8

or,    2x = 8

 or, x = 4

so, no. of boys = 7*4 = 28

  no. of girls = 5*4 = 20

Answered by Anonymous
45

{\mathfrak{\red{\underline{\underline{Answer:-}}}}}

Number of boys = 7x = 7 × 4 = 28

Number of girls = 5x = 5 × 4 = 20

Total class strength = 28 + 20 = 48 students

{\mathfrak{\red{\underline{\underline{Explanation:-}}}}}

Let the common ratio between the number of boys and numbers of girls be x.

Number of boys = 7x

Number of girls = 5x

According to the given question,

Number of boys = Number of girls + 8

∴ 7x = 5x + 8

On transposing 5x to L.H.S, we obtain

7x − 5x = 8

2x = 8

On dividing both sides by 2, we obtain

\sf{\dfrac{2x}{2}=\dfrac{8}{2}}

x = 4

Number of boys = 7x = 7 × 4 = 28

Number of girls = 5x = 5 × 4 = 20

Hence, total class strength = 28 + 20 = 48 students

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