Question

The number of Ca2+ and clº ions present in anhydrous CaCl, is 3.01 x 1023 and 6.023 x 1023 respectively. The weight of the anhydrous sample is - (1) 40 g 2) 55.5 g (3) 222 g (4) 75.5 g​

Answer 1

The number of Ca2+ and cl ions present in anhydrous CaCl, is 3.01 x 1023 and 6.023 x 1023 respectively.

2) 55.5 g I think so ☺️

Answer 2

I hope the compound is CaCl2. In 1 mole CaCl2, 2 mole chloride ion is present. Here, 1 mole chloride ion is present, therefore, the anhydrous sample is just 0.5 mole. Molar mass of CaCl2=40+35.5*2=40+71=111g. Therefore, 0.5 mole weight=55.5g
Mark me brainliest pls