the number of carbon atoms present in 2.8 grams of carbon monoxide
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Answered by
12
Heya..
Molecular mass of CO = 12u + 16u
= 28u.
Hence 28 g of CO have 6.023* 10^23 molecules of CO
Hence 2.8 g of CO have 6.023 * 10^23 /10 molecules of CO
=) 6.023* 10^22 molecules of CO
Hence number of carbon atoms in 28g of CO = 1 * 6.023* 10^22 atoms of Carbon
= 6.022 * 10^22 atoms of Carbon
Hope it's helpful to u.
Molecular mass of CO = 12u + 16u
= 28u.
Hence 28 g of CO have 6.023* 10^23 molecules of CO
Hence 2.8 g of CO have 6.023 * 10^23 /10 molecules of CO
=) 6.023* 10^22 molecules of CO
Hence number of carbon atoms in 28g of CO = 1 * 6.023* 10^22 atoms of Carbon
= 6.022 * 10^22 atoms of Carbon
Hope it's helpful to u.
Answered by
0
Answer:
6*10^22
Explanation:
it is correct answer
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