Question

the number of carbon atoms present in 2.8 grams of carbon monoxide

Answer 1

Heya..

Molecular mass of CO = 12u + 16u

= 28u.

Hence 28 g of CO have 6.023* 10^23 molecules of CO

Hence 2.8 g of CO have 6.023 * 10^23 /10 molecules of CO

=) 6.023* 10^22 molecules of CO

Hence number of carbon atoms in 28g of CO = 1 * 6.023* 10^22 atoms of Carbon

= 6.022 * 10^22 atoms of Carbon

Hope it's helpful to u.

Answer 2

Answer:

6*10^22

Explanation:

it is correct answer