Question

the number of chromatids present in a human cell in G2 phase ,prophase,post-cytokinesis G1 phase , respectively are
1.92-92-46-46
2.46-92-92-46
3.92-46-46-92
4.46-46-23-23
(give the reason for your answer this is an mcq)​

Answer 1

in s phase it doubles46*2=92

g2 & prophase =92

g1 not still duplicated =46

post cytokinesis 46

Answer 2

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HERE IS YOUR ANSWER⤵

✔According to me the correct option will be option 1.

EXPLAINATION: There are 46 chromosomes in a human cell. And 1 chromosome has 2 chromatids. Therefore, 46 chromosomes will have 92 chromatids. Hence, In G2 phase the number of chromatids will be 92. You may think that S happens occurs before G2 phase but remember In S phase only the amount of DNA is doubled but the number of chromosomes remain same. That is why even after S phase the number of chromatids and chromosomes remains same. In prophase the number of chromatids will be 92 because it is a part of mitosis division and we know that mitosis is a equational division. In post-cytokinesis the chromosomes becomes half as it gets distributed into 2 cells equally so here the numner of chromatids becomes 46. And then in G1 phase it remains 46 as G1 phase is the phase between M and S phase.

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