The number of circular pipes with an inside diameter of 1cm which will carry the same amount of water as a pipe with an inside diameter of 8cm is a) 16 b) 36 c) 49 d) 64
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The number of circular pipes required is (d) 64.
Assuming length of pipes to be same.
Volume of shorter pipes will be equal to volume of longer pipe.
Thus, A1*L1 = A2*L2
L1=L2.
A=πr²
Let the number of pipes required is n.
So, Nr1²= r2²
N * (1/2)² = (8/2)²
N*0.5²= 4²
N= 16/0.25
N= 64.
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