The number of degrees of freedom associated with 1 g of helium at S.T.P. is (Atomic weight of helium = 4 g)
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since helium is a monoatomic gas therefore number of degree of freedom is
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tapasranjan0929:
4g of He= 6.203×10^23 no of atoms .
4gm of He =6.023*× 10^23 no of atoms. For 1gm it will be 1.5×10^23. so total no of degree of freedom is (1.5×10^23)×3 = 4.5×10^23.
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Answer:4.5×10^23
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