Question

The number of different six digit numbers, the sum of whose digits is odd is a) 1062 b) 6! × 106 c) 9 X 105 d) 45 x 104

Answer 1

Answer:

For six digit number..

No of Ways in which 1 digit can be select =9...(0 can not be first digit)

Remaining 5 digit number can be arrange in  =10ⁿ=10^5 ways

Sum of digits to be odd ...

e+e+e+e+e+o

e+e+e+o+o+o

e+o+o+o+o+o

(where even =e odd =o)

to sum be odd..either 1 , 3 or 5 no must be odd ..so probability is half of 9*10^5...

(9*10^5)/2=45*10^4

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