the number of different terms in the binomial expansion of (1+x)^10 + (1-x)^10 is
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Answer:
Step-by-step explanation:
(1+x)
101
(1−x+x
2
)
100
can be written as
=(1+x)(1+x)
100
(1−x+x
2
)
100
=(1+x)[(1+x)(1−x+x
2
)]
100
=(1+x)(1+x
3
)
100
=(1+x
3
)
100
+x(1+x
3
)
100
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