Question

the number of dry cell each of emf 1.5v and internal resistance 0.5ohm that must be joined in series with resistance of 20ohm so as to send a current of 0.6ampere through the circuit

Answer 1

Answer:

Explanation:

Here the law I=V/R is applied. I have attached the answer down. Hope it will help you.

Answer 2

The number of dry cells of emf 1.5v and internal resistance 0.5 ohm required is equal to 10.

Let the number of dry cells required be equal to n.

The net emf of the circuit = E = 1.5n V

The equivalent resistance of the circuit = R = (20 + 0.5n) ohm

Given that the curved flowing through the circuit = I = 0.6 A

I = E/R

=> 0.6 = 1.5n / 20+0.5n

=> 12 + 0.3n = 1.5n

=> 12 = 1.2n

=> n = 10

The number of dry cells required in the circuit = 10