Question

The number of Electric lines of force radiating from a closed surface in vacuum is 1.13×10^11. The charge enclosed by the surface is

1 coulomb

1 micro-coulomb

0.1 coulomb

0.1 micro-coulomb​

Answer 1

Answer:

1 coulomb

Explanation:

take 1.13×10^11 as total flux from the surface.

using gauss law,

charge enclosed by surface=1.13×10^11×E•=1.13×10^11×8.85×10^-12=1

Answer 2

Given:

The number of electric lines of force radiating from a closed surface in vacuum= 1.13X 10¹¹

To find:

The charge enclosed by the surface

Solution:

Using Gauss Law of electrostatics,

The number of electric lines of force = Q enclosed by the surface / εο

Here, εο = 8.85X10⁻¹² C²/N.m²

or $\phi = \frac{Q_e_n_c_l_o_s_e_d}{\epsilon_O}$

Substituting the values,

1.13X 10¹¹ = Qenc / 8.85X10⁻¹²

or Qenc = 8.85X10⁻¹² X 1.13X 10¹¹

= 8.85 X 1.13 / 10

= 1C

Thus the charge enclosed by the surface is 1 coulomb.