The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 sec is (charge on electron = 1.60*10-19 c)
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as q= n* so no of electrons = q/ I*t
no of electrons =( 1.6* 10-19)/ 1*60
= 2.67*10∧-21
Explanation:
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