Question

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 second is

Answer 1

Given current, i = 1 Amp and time taken, t = 60sec
So, charge = i × t = 1 × 60 = 60 Coulombs

∵ 96500 C charges are equivalent 1 mole of electrons
∴ 1 C charge is equivalent with 1/96500 mole of electrons
∴ 60C charges are equivalent with 60/96500 mole of electrons

Hence, mole of electrons = 6/9650
so, the number of electrons = 6/9650 × 6.023 × 10²³
= 0.003744 × 10²³
= 3.744 × 10²⁰

Answer 2

Answer: 3.75 x 10 * 20

Explanation: q= nxe and

q =ixt

ixt= nxe then n= ixt/e

1x 60/1.6*10-19 gives 3.75x 10*20