The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 second is
Answers
Answered by
229
Given current, i = 1 Amp and time taken, t = 60sec
So, charge = i × t = 1 × 60 = 60 Coulombs
∵ 96500 C charges are equivalent 1 mole of electrons
∴ 1 C charge is equivalent with 1/96500 mole of electrons
∴ 60C charges are equivalent with 60/96500 mole of electrons
Hence, mole of electrons = 6/9650
so, the number of electrons = 6/9650 × 6.023 × 10²³
= 0.003744 × 10²³
= 3.744 × 10²⁰
So, charge = i × t = 1 × 60 = 60 Coulombs
∵ 96500 C charges are equivalent 1 mole of electrons
∴ 1 C charge is equivalent with 1/96500 mole of electrons
∴ 60C charges are equivalent with 60/96500 mole of electrons
Hence, mole of electrons = 6/9650
so, the number of electrons = 6/9650 × 6.023 × 10²³
= 0.003744 × 10²³
= 3.744 × 10²⁰
Answered by
20
Answer: 3.75 x 10 * 20
Explanation: q= nxe and
q =ixt
ixt= nxe then n= ixt/e
1x 60/1.6*10-19 gives 3.75x 10*20
Similar questions