Question

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds

Answer 1

Q=N*e

Where Q=Charge, N=no. of electrons, e=Charge of 1 electron.

Q=I*t

Where I=Current, t=Time

∴ Q=1*60

Q=60C    (C=coulumb)

∵ 96500 C charges are equivalent 1 mole of electrons  

∴ 1 C charge is equivalent with 1/96500 mole of electrons  

∴ 60C charges are equivalent with 60/96500 mole of electrons

⇒ mole of electrons = 6/9650  

so, the number of electrons = 6/9650 × 6.023 × 10²³  

= 0.003744 × 10²³  

= 3.744 × 10²⁰

Please mark it as brainliest.

Answer 2

Answer:

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