Question

the number of electrons in 2 gram Ion of nitrate no3^-1 is​

Answer 1

Answer:

1 Mole of NO_{3} = 55g = 6.022*10^{23} molecules

Molecules in 2g od nitrate = \frac{6.022*10^{23}}{55}*2 = 2.19*10^{22}

Valence electrons in one ion (molecule) of NO_{3} = 24

Valence electrons in 2.19*10^{22} ions of NO_{3} = 5.256*10^{23} .

Hope its help for You ➡➡