Question

The number of electrons present in 1.8 ml water is

Answer 1

Answer:

The number of electrons in 1.8mL of H_{2} O is 6.023 \times 10^{23}

Explanation:

Number of moles

We know that the quantity of water given is 1.8 ml which contains a molar mass of water is 18.

So the number of moles of water= 1.8÷18=0.1

The number of electrons in 1 atom of water= 10

1 mole of water or 1 atom of water=

So, there are electrons in 1 mole of water ,

The number of electrons contained 1.8 ml of water or 0.1 mole of water= \bold{0.1 \times 10 \times 6.023 \times 10^{23}=6.023 \times 10^{23}} electrons.

Answer 2

6.023*10 is the right answer