Question

The number of hydrogen atoms present in 0.425 gram of nh3

Answer 1

molar weight of NH3= 17 g

number of moles of NH3 present in 0.425g of NH3

= 0.425/17=25/1000=0.025moles

now, 1 molecule of NH3 have 3 H-atom

so , 0.025 moles of NH3 will have (3×0.025)moles of H-atom

i.e; = 0.075 moles of H-atom

so number of H-atom= (6.022×10²³×0.075)