Chemistry, asked by sengarayush89, 11 months ago

The number of electrons, protons, neutrons present
in the tripositive ion of COS® respectively are
1) 27,59,27 2) 27,26,32
3) 24, 27,32 4) 27,25,32
O
1
O
O
O​

Answers

Answered by advocatehmh
0

Answer: mi y a t a jtfi5f7. C VB fax Keyes ln zt

Explanation: of kuzzj kdo7t

Answered by Qwkerela
1

The correct question is:

The number of electrons, protons, neutrons present in the tripositive ion  Co^{3+} respectively are:

The Main Answer is:  (3) 24, 27, 32

Given: Tripositive ion - Co^{3+}

To Find: The number of electrons, protons, and neutrons in the given ion.

Solution:

The atomic symbol for Co atom is- \frac{59}{27} Co

Here, 59 is the mass number

And 27 is the atomic number.

We know, that the number of protons = atomic number = 27

And, mass number = no. of protons + no. of neutrons

⇒ 59 = 27 + no. of neutrons

no. of neutrons = 32  

Also, in a neutral atom

no. of electrons = no. of protons = 27 (for Co)

But,

we have Co^{3+}

Here, the ion has a positive charge of 3.

This means that there are 3 more protons than the no. of electrons.

As the no. of protons is fixed for any atom, therefore, in this case, the no. of electrons is 3 less than usual, i.e.,

no. of electrons = 27 - 3 = 24

Therefore, the no. of electrons, protons, and neutrons is 24, 27, and 32 respectively.

#SPJ3

Similar questions