The number of electrons, protons, neutrons present
in the tripositive ion of COS® respectively are
1) 27,59,27 2) 27,26,32
3) 24, 27,32 4) 27,25,32
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Answers
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The correct question is:
The number of electrons, protons, neutrons present in the tripositive ion respectively are:
The Main Answer is: (3) 24, 27, 32
Given: Tripositive ion -
To Find: The number of electrons, protons, and neutrons in the given ion.
Solution:
The atomic symbol for Co atom is-
Here, 59 is the mass number
And 27 is the atomic number.
We know, that the number of protons = atomic number = 27
And, mass number = no. of protons + no. of neutrons
⇒ 59 = 27 + no. of neutrons
⇒ no. of neutrons = 32
Also, in a neutral atom
no. of electrons = no. of protons = 27 (for Co)
But,
we have
Here, the ion has a positive charge of 3.
This means that there are 3 more protons than the no. of electrons.
As the no. of protons is fixed for any atom, therefore, in this case, the no. of electrons is 3 less than usual, i.e.,
no. of electrons = 27 - 3 = 24
Therefore, the no. of electrons, protons, and neutrons is 24, 27, and 32 respectively.
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