Question

the number of electrons with the azimutal quantum no. L =1and L=2 in ground state of Cr is respectively ​

Answer 1

●》For Cr, Z=24

●》Electronic configuration will be:

$1s {}^{2} \: 2s {}^{2} \: 2p {}^{6} \: 3s {}^{2} \: 3p {}^{6} \: 4s {}^{1} \: 3d {}^{5}$

• For l = 1, we have electrons of p orbital

=> 12 electrons

• For l = 2, we have electrons of d orbital

=> 5 electrons

Therefore, answer is 12 and 5

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