The number of factors of 5,83,200 which are perfect cubes are
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Let B denotes set of numbers, which are perfect cubes. If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have. 2(0 or 3 or 6or 9)—– 4 factors. 3(0 or 3 or 6) —– 3 factors.
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