Question

The number of four digited even numbers that can be.
formed with the digits a 1,2,5,7,8​

Answer 1

Answer:

For even no, last digit could

be 0,2,4,6

But first digit cannot be 0

So : I:6×5×4=120

II:5×5×4=100

III:5×5×4=100

IV:5×5×4=100

∴ Total no.of 4 digit even

no. =120+100+100+100

=420

Answer 2

Explanation:

→ First, let us find the total no. of four digit arrangement

→ Even digits = 2,8,0 [3digits]

5 4 3 3

Total no of cases = 5 x 4 x 3 x 3

= 180

→ Excluding the ones that start with 0.

0 4 3 2

→ This time, the last can take 1 of 2 options

only (2,8)

No. of numbers starting with 0 = 4 x 3 x 2 = 24

Ans=180−24=156

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