Question

the number of gram molecules of oxygen in 6.02*10^24 CO molecule is

Answer 1

Answer:

So 6.02x10^24 CO molecules contain6.02x10^24 atoms of O which is equal to 10gm-atoms of oxygen. Since Oxygen is diatomic,10 g-atom = 1/2x10 g-molecule of Oxygen = 5gram-molecule of O2 = 5grams of O2 molecule. Please mark it as brainliest!! CO molecule is5.

Answer 2

1 mole CO equivalent to 6.02x10^23molecules of CO contain 6.02x10^23atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.