Question

The number of halide ions in [Pt ( NH 3 ) 3 Cl 2 Br ] Cl is

Answer 1

Answer:

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Explanation:

[Pt(NH3)Cl2 Br]Cl⇌[Pt(NH3 )Cl2 Br] + +Cl −

The number of precipitable halide ions in the sample [Pt(NH3)Cl2Br]Cl will be 1 since only 1 free chloride or halide ion is formed when dissolved in the solvent.

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Answer 2

Answer:

Number of halide ions in $[Pt(NH_{3} )_{3}Cl_{2} Br]Cl$  is 1.

Explanation:

$[Pt(NH_{3} )_{3}Cl_{2} Br]Cl$ dissociates into its respective ions according to the following equation:

$[Pt(NH_{3} )_{3}Cl_{2} Br]Cl$ → $[Pt(NH_{3} )_{3}Cl_{2} Br]^{+}+Cl^{-}$

Total number of ions = 2

Since we get only 1 chloride ion in solution, the number of halide ions = 1

Chloride ion is free to dissociate when the complex dissolves in water. Other atoms/molecules are bound to the central metal atom, that is platinum ion. The atoms/molecules within the coordination sphere won't dissociate.