Question

The number of hexagonal faces that are present in a truncated octahedron is ______.

Answer 1

In geometry, the truncated octahedron is an Archimedean solid. It has 14 faces (8 regular hexagonal and 6 square), 36 edges, and 24 vertices. Since each of its faces has point symmetry the truncated octahedron is a zonohedron.

Faces by sides: 6+8

Symmetry group: Oh, B3,, (*432), order 48; Th,, and (*332), order 24

Type: Archimedean solid; Uniform polyhedron