The number of hours spent by Ashu, a school student on vanous
activities on a working day are given below
Activity Sleep school HW | Tution out of home outdoor games Other Acti at home
A friend Sonu came to his house to study together. What is the
probability that
1) Ashu is available at home.
#) Ashu's friend will play with Ashu.
Answers
total activities=5 (sleep, school homework, tuition, outdoor games, other activities at home)
he is at home for 3 activities (sleep, school homework, other activities at home)
1) Ashu is available at home
P(E)=favourable cases/total cases
=3/5
=0.6
2) ashes friend will play with Ashu
he is free at home for playing= 1 case(other other activities at home)
P(E) =favourable cases/total gases
=1/5
= 0.2
Answer:
Total activities=5(sleep, school, homework, tuition, outdoor games,other activities at home)
He is at home for 3 activities (sleep,school, homework, other activities at home)
1 Ashu is available at home
P(E)= favourable cases/total cases
=3/5
=0.6
2.Ashu's friend will play with Ashu
He is free at home for playing=1 case (other activities at home)
P(E)= favourable cases/total gases
=1/5
=0.2