The number of integer values which are in the domain of the function f(x) = sqrt(x+1)(x - 2) / (x + 5)(6 - x)
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Step-by-step explanation:
(−2≤x<0)∪(0<x<1)
f(x)=log10(1−x)1+(x+2)
For this function to be defined, (1−x)>0,=1 and (x+2)≥0
⇒x<1,=0 and x≥−2
Thus domain of f(x) is x∈[−2,0)∪(0,1)
I hope it's help you
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