Math, asked by harshith8143, 11 hours ago

The number of integer values which are in the domain of the function f(x) = sqrt(x+1)(x - 2) / (x + 5)(6 - x)​

Answers

Answered by jjasmeen012
0

Step-by-step explanation:

(−2≤x<0)∪(0<x<1)

f(x)=log10(1−x)1+(x+2) 

For this function to be defined, (1−x)>0,=1 and (x+2)≥0

⇒x<1,=0 and x≥−2

Thus domain of f(x) is x∈[−2,0)∪(0,1)

I hope it's help you

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