The number of integers a in the interval (1, 2014 for which the system of
equations
22
I +y = a;
+
1
has finitely many solution is
y?
y - 1
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0
Answer:
Correct option (C) 2013 Explanation: a ≠ 2 [for a = 2 infinitely many solutions] always +ve there two real solutions. a ≠ 2 and a ∈ [1, 2014] Total 2014 – 1 = 2013 values
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